You visited us 1 times! Enjoying our articles? Unlock Full Access!

pH of Acids and Bases

What is the ...

Question

What is the $p H$ of a solution in which $25.0 m L$ of the $0.1 M N a O H$ is added to $25 m L$ of $0.08 M H C l$ and final solution is siluted to $500 m L$ ?

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

11

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

13

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $11$
After mixing remaining conc. of $O H^{-} = 0.1 - 0.08 = 0.02$ .
And volume is 500 ml so molarity = 0.001M.
So pOH $= 3; p H = 14 - p O H = 11$ .

Suggest Corrections

Similar questions

p H

25 m L

0.1 M H C l

50 m L

0.01 M H N O_{3}

25 m L

0.1 M N a O H

100 m L

0.1 M

H_{3} P O_{4}

200 m L

0.1 M

N a O H

p H

G i v e n K_{a 1} = 10^{- 3}, K_{a 2} = 10^{- 8}, K_{a 3} = 10^{- 13}

H_{2} S O_{4}

N a O H

H^{+}

O H^{-}

H C l

H C l

H C l

75 m l

0.2 M H C l

25 m l

1 M H C l

300 m l

p H

Join BYJU'S Learning Program