wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the pH of a solution in which 25 mL of 0.1 M NaOH is added to 25 mL of 0.08 M HCl and final solution is diluted to 500 mL?

A
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
11
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
13
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 11
Milli-equivalents of HCl=25×0.08=2
Milli-equivalents of NaOH=25×0.1=2.5
As milli-equivalents of NaOH is more than milli-equivalents of HCl, then the remaining concentration of [OH]=2.52500=103
[H+]=1011
pH=log(1011)=11

flag
Suggest Corrections
thumbs-up
31
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hydrolysis
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon