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Question

What is the pH of Ca(OH)2 solution having a concentration of 5×108 M ?
Take log(6.18)=0.79

A
8.99
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B
7.21
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C
5.69
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D
6.01
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Solution

The correct option is B 7.21
Here very dilute solution of Ca(OH)2 is given, where water dissociation needs to be considered to calculate the total [OH] ions present in the solution.
[OH] from Ca(OH)2=2×5×108 M=107 M.

H2O (l)H+ (aq)+OH (aq)

From H2O ,
[OH]=[H+] = x
We know,
[H+][OH]=1014x(107+x)=1014x2+107x1014=0x=107±1014+4×10142x=6.18×108

So, [H+]=6.18×108 MpH=log[H+]pH=log(6.18×108)=(80.79)pH=7.21

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