Question

what is the physical state of water at 98 degree farenheit

Answer 1

Dear Student
$$\begin{gathered} Convert98degreeFahrenheittodegreeCelsius \\ \frac{5\left(T^{o}F-32\right)}{9}=T^{o}C \\ \frac{5\left({98}^{o}F-32\right)}{9}=36.{67}^{o}C \end{gathered}$$
Water exists in gaseous state above its boiling point that is above100⁰ C and liquid state below its boiling point.. That is, water exists as liquid state at 98⁰ F.

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