What is the pOH of a solution containing hydrogen ion concentration of 1 - 10-8 M -A- 7-04B- 0-8C- 8D- None of the above

At 25^∘C, K_w=10^ 14 So, pK_w=14 Total concentration of nbsp;[H^+] = 10^ 8 For calculating pOH, we have to find pH first: Remember pH= log_10[H^+] pH= log ...

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Standard XII

Physics

Com of Solid Bodies

What is the p...

Question

What is the $p O H$ of a solution containing hydrogen ion concentration of $1 \times 10^{- 8} M ?$

7.04

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0.8

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None of the above

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Solution

The correct option is A 7.04
Here $[H^{+}]$ comes from water:
Total concentration of $[H^{+}] = 10^{- 8} + 10^{- 7}$
For calculating pH we have to find pH first:
$R e m e m b e r p H = - l o g_{10} [H^{+}]$

$p H = - l o g_{10} [10^{- 7} + 10^{- 8}] = 6.96$

$W e k n o w : p H + p O H = 14 6.96 + p O H = 14 \Rightarrow p O H = 14 - 6.96 = 7.04 p O H = 7.04$

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Com of Solid Bodies

Standard XII Physics

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What is the pOH of a solution containing hydrogen ion concentration of 1×10−8 M ?

The correct option is A 7.04 Here [H+] comes from water: Total concentration of [H+] =10−8+10−7 For calculating pH we have to find pH first: Remember pH=− log10[H+] pH=− log10[10−7+10−8]=6.96 We know:pH+pOH=146.96+pOH=14⇒pOH=14−6.96=7.04pOH=7.04

What is the $p O H$ of a solution containing hydrogen ion concentration of $1 \times 10^{- 8} M ?$