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Question
What is the pOH of HCl solution having concentration of 1×10−9 M ?
What is the pOH of HCl solution having concentration of 1×10−9 M ?
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Solution
The correct option is C 7.01
HCl⇌H++ Cl−
[H+]from HCl=10−9
Let x be the [H+]ion from H2O
H2O⇌ H++ OH− (x+10−9) x[H+] [OH−]=10−14(x+10−9)x=10−14(x+10−9)x−10−14=0x2+10−9x−10−14=0x=−10−9±√(10−9)2+4×10−142 x=9.95×10−8pH=−log10(9.95×10−8+10−9)pH≈−log(1.005×10−7)pH=7−0.01=6.99pOH=14−6.99=7.01
HCl⇌H++ Cl−
[H+]from HCl=10−9
Let x be the [H+]ion from H2O
H2O⇌ H++ OH− (x+10−9) x[H+] [OH−]=10−14(x+10−9)x=10−14(x+10−9)x−10−14=0x2+10−9x−10−14=0x=−10−9±√(10−9)2+4×10−142 x=9.95×10−8pH=−log10(9.95×10−8+10−9)pH≈−log(1.005×10−7)pH=7−0.01=6.99pOH=14−6.99=7.01
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