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Question

What is the pOH of HCl solution having concentration of 1×109 M ?

A
9
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B
8.95
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C
7.01
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D
None of the above
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Solution

The correct option is C 7.01
HClH++ Cl
[H+]from HCl=109
Let x be the [H+]ion from H2O
H2O H++ OH (x+109) x[H+] [OH]=1014(x+109)x=1014(x+109)x1014=0x2+109x1014=0x=109±(109)2+4×10142 x=9.95×108pH=log10(9.95×108+109)pHlog(1.005×107)pH=70.01=6.99pOH=146.99=7.01

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