What is the polar of the point (2, 3) with respect to the circle x2+y2 − 2x − 4y − 4 = 0
x + y = 12
[x+y=12]
This can be found by the formula T = 0
Given equation is x2+y2 − 2x − 4y − 4 = 0
i.e., 2x + 3y − (x+2) − 2(y+3) − 4 = 0
x + y − 2 − 6 − 4 = 0
x + y = 12