What is the polynomial identity used in the diagram?

16 x^{2} - 1 = (4 x + 1) (4 x - 1)

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16 x^{2} + 1 = (4 x + 1) (4 x - 1)

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16 (4 x - 1)

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4 x (4 x + 1)

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Solution

The correct option is D $16 x^{2} - 1 = (4 x + 1) (4 x - 1)$
The given identity is $(4 x + 1) (4 x - 1) = (4 x)^{2} - 1^{2}$
Area of full square $=$ area of pink rectangle $+$ area of blue rectangle.
i.e., $(4 x)^{2} - 1^{2} = 4 x (4 x - 1) + 1 (4 x - 1)$
$(4 x)^{2} - 1^{2} = (4 x + 1) (4 x - 1)$
So, $16 x^{2} - 1 = (4 x + 1) (4 x - 1)$ is used in the diagram.

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Similar questions

(4 x + 1) (4 x - 1) =

(4 x + 1) (4 x - 1)

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