Question

What is the potential difference across a $64.0$ microfarad capacitor if the charge on the positive plate is $+16.0$ microcoulombs?

• A. $4.0V$
• B. $0.25V$
• C. $1024V$
• D. $2.0V$
• E. $32.0V$

Answer 1

Answer: (B)

$0.25V$

Charge on the capacitor $Q=16.0$ $\mu$C

Capacitance of the capacitor $C=64.0$ $\mu F$

$\therefore$ Potential difference across it $V=\frac{16.0\mu }{64.0\mu }=0.25$ volts