Question

What is the potential differences across a 64.0 microfarad capacitor if the charge on the positive plate is +16.0 micro coulombs?

• A. 4.0 V
• B. 0.25 V
• C. 1024 V
• D. 2.0 V
• E. 32.0 V

Answer 1

The correct option is B 0.25 V

Given : Capacitance $C=64.0\mu F$ Charge $Q=16.0\mu$C

Thus potential difference across the capacitor $V=\frac{Q}{C}=\frac{16\mu C}{64\mu F}=0.25$ volts