Question

What is the potential energy of electron in the L-shell of the hydrogen atom?

• A. -13.6 eV
• B. -6.8 eV
• C. -10.2 eV
• D. -1.7 eV

Answer 1

The correct option is D -1.7 eV

The principal quantum number for L-shell is 4

we know that energy of an electron in nth bohr's orbit is given by,

$E_n=-\frac{13.6eV}{n^2}$

but Potential energy of electron=$-2\left(E_n\right)=-\frac{27.2eV}{n^2}$

Therefore, for $n=4$ $P.E=-\frac{27.2eV}{16}=-1.7eV$