What is the potential energy of the system of the three charges if $q_{3}$ is placed at $x = + 10.0 c m$ ?

- 1.8 \times 10^{- 7} J

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- 3.6 \times 10^{- 7} J

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+ 3.6 \times 10^{- 7} J

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+ 1.8 \times 10^{- 7} J

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Solution

The correct option is D $- 3.6 \times 10^{- 7} J$
PE of system $= \frac{1}{4 π ϵ} \frac{q_{1} q_{2}}{0.2} + \frac{1}{4 π ϵ} \frac{q_{2} q_{3}}{0.1} + \frac{1}{4 π ϵ} \frac{q_{3} q_{1}}{0.1} = - 3.6 \times 10^{- 7} J$

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What is the potential energy of the system of the three charges if q3 is placed at x=+10.0cm?

The correct option is D −3.6×10−7JPE of system =14πϵq1q20.2+14πϵq2q30.1+14πϵq3q10.1=−3.6×10−7J

What is the potential energy of the system of the three charges if $q_{3}$ is placed at $x = + 10.0 c m$ ?

The correct option is D $- 3.6 \times 10^{- 7} J$
PE of system $= \frac{1}{4 π ϵ} \frac{q_{1} q_{2}}{0.2} + \frac{1}{4 π ϵ} \frac{q_{2} q_{3}}{0.1} + \frac{1}{4 π ϵ} \frac{q_{3} q_{1}}{0.1} = - 3.6 \times 10^{- 7} J$