Question

What is the potential of a half cell consisting of zinc electrode in 0.01 M $ZnS{O}_4$ solution of ${25}^{o}C?[E^o=0.763V]$

Answer 1

The half cell reaction is $Zn\to Z{n}^{2+}+2e^{-}$
The Nernst equation for the oxidation half- cell reaction is $E=E^0-\frac{0.0591}{n}\log \left[Z{n}^{2+}\right]$
The number of electrons transferred $n=2$ and $E_o=0.763V$
substituting these values in the Nernst equation
we have, $E=0.763-\frac{0.0591}{2}\log [-2]$
$E=0.793+0.0591=0.8221$ $V$ $\left(0.8221V\right)$