What is the precipitate produced from the double displacement reaction of an aqueous solution of lead (II) nitrate and an aqueous solution of Potassium sulfate?

P b {S O}_{4}

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K N O_{3}

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K_{2} P b

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N O_{2}

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S O_{3}

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Solution

The correct option is A $P b {S O}_{4}$
Option $A$ is the correct answer.
The equation can be written as ${P b {(N O}_{3})}_{2}$ $+$ $K_{2} S O_{4}$ $=$ ${P b S O}_{4}$ $+$ ${2 K N O}_{3}$
This ${P b S O}_{4}$ forms a precipitate.

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Similar questions

Q. When double displacement reaction of an aqueous solution of lead (II) nitrate and aqueous solution of potassium sulfate occurs, precipitate form will be?

Q. In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate solution, a yellow precipitate of lead iodide is obtained. While performing the activity if lead nitrate is not available, which of the following can be used in the place of lead nitrate?

$P b (N O_{3})_{2} (a q) + 2 K C l (a q) \to 2 K N O_{3} (a q) + P b C l_{2} (s)$

When lead nitrate solution is mixed with potassium chloride solution, a precipitate of lead chloride and potassium nitrate solution are formed. This type of reaction is called _________________.

Question 13

In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate?

(a) Lead sulphate (insoluble)
(b) Lead acetate
(c) Ammonium nitrate
(d) Potassium sulphate

$P b (N O_{3})_{2} (a q) + 2 K C l (a q) \to 2 K N O_{3} (a q) + P b C l_{2} (s)$

When lead nitrate solution is mixed with potassium chloride solution, a precipitate of lead chloride and solution of potassium nitrate are formed. This type of reaction is called _________________.

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What is the precipitate produced from the double displacement reaction of an aqueous solution of lead (II) nitrate and an aqueous solution of Potassium sulfate?

The correct option is A PbSO4Option A is the correct answer.The equation can be written as Pb(NO3)2 + K2SO4 = PbSO4 + 2KNO3This PbSO4 forms a precipitate.

The correct option is A $P b {S O}_{4}$
Option $A$ is the correct answer.
The equation can be written as ${P b {(N O}_{3})}_{2}$ $+$ $K_{2} S O_{4}$ $=$ ${P b S O}_{4}$ $+$ ${2 K N O}_{3}$
This ${P b S O}_{4}$ forms a precipitate.