Question

What is the pressure exerted by a man weighing $80kg$ standing on his feet? Area of his feet $=160sq.cm.(Takeg=10m{s}^{-2})$.

Answer 1

Given : Wieght of the man $\left(W\right)=mg=80\times 10=800N$
$Area=160sqcm=160\times \frac{1}{100\times 100}sqm$
$=16\times {10}^{-3}{m}^2$
$\therefore Pressure\left(P\right)=\frac{Force}{Area}=\frac{800N}{16\times {10}^{-3}{m}^2}$
$=5\times {10}^{4}N{m}^{-2}$.