Question

What is the prime factorization of $16x^2-64$?

• A. $16(x^2-4)$
• B. $16(x-2)(x+2)$
• C. $4\times 4(x-2)(x+2)$
• D. $2\times 2\times 2\times 2(x-2)(x+2)$

Answer 1

The correct option is D $2\times 2\times 2\times 2(x-2)(x+2)$

$16x^2-64=16(x^2-4)=16(x-2)(x+2)$
$=2\times 2\times 2\times 2(x-2)(x+2)$