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Question

What is the principal solution of 4 cos2x8 cos x+3=0 ?


A

x=π6

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B

x=π4

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C

x=π3

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D

x=π2

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Solution

The correct option is C

x=π3


4 cos2x8 cos x+3=04 cos2x8 cos x+4=1(2cos x2)2=12cos x2=±12cos x=3 not possible2cos x=1cos x=12x=π3


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