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Uses of Alkaline Earth Metals

What is the p...

Question

What is the principle of the following reaction?
$C a (O H)_{2} + M g C l_{2} \to M g (O H)_{2} + C a C l_{2}$

Solubility of

M g (O H)_{2}

= Solubility of

C a (O H)_{2}

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Solubility of

M g (O H)_{2}

< Solubility of

C a (O H)_{2}

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Solubility of

M g (O H)_{2}

> Solubility of

C a (O H)_{2}

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None of these

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Solution

The correct option is B Solubility of $M g (O H)_{2}$ < Solubility of $C a (O H)_{2}$
The principle of the following reaction, $C a (O H)_{2} + M g C l_{2} \to M g (O H)_{2} + C a C l_{2}$ is:
Solubility of $M g (O H)_{2}$ < Solubility of $C a (O H)_{2}$
Due to this, most of the magnesium hydroxide precipitates out as soon as it is formed.
Option B is correct.

Suggest Corrections

Similar questions

H_{2} O ?

(1) B e S O_{4} > M g S O_{4} > C a S O_{4} > B a S O_{4}

(2) B e (O H)_{2} > M g (O H)_{2} > C a (O H)_{2} > B a (O H)_{2}

(3) L i O H < N a O H < K O H < R b O H

(4) L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3}

M g (O H)_{2}

K_{s p}

8.9 \times 10^{- 13}

N H_{4} O H

C a (O H)_{2}

M g (O H)_{2}

0.1 M N a O H

M g (O H)_{2}

1.8 \times 10^{- 11}

C a (O H)_{2}

H_{2} O

B e S O_{4} > M g S O_{4} > C a S O_{4} > B a S O_{4}

B e (O H)_{2} > M g (O H)_{2} > C a (O H)_{2} > B a (O H)_{2}

L i O H < N a O H < K O H < R b O H

L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3}

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