Question

What is the probability of getting a multiple of 3 in a single throw of a dice?

• A. $\frac{2}{3}$
• B. $\frac{1}{6}$
• C. $\frac{2}{5}$
• D. $\frac{1}{3}$

Answer 1

The correct option is D $\frac{1}{3}$

Possible outcomes when a dice is thrown is 1, 2, 3, 4, 5, 6.
Out of which 3 and 6 are multiples of 3.
So, number of favourable outcomes = 2
So, total number of outcomes = 6
Probability = $\frac{Numberoffavourableoutcomes}{Totalnumberofoutcomes}$
=$\frac{2}{6}$
=$\frac{1}{3}$