What is the probability of getting a prime number when a die is rolled?

1/6

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1/2

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1/3

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2/5

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Solution

The correct option is B
1/2

Number of prime outcomes when a die is rolled is 3 as 2, 3, 5 are the prime outcomes. Total outcomes = 6. So total probability is $\frac{3}{6}$ = $\frac{1}{2}$

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Q. The probability of getting a prime number when a die is rolled is

\frac{1}{2}

Question 77

The probability of getting number 6 in a throw of a die is $\frac{1}{6} .$ Similarly, the probability of getting a number 5 is $\frac{1}{5} .$

When a die is thrown 10 times, the following outcomes are noted: 1, 3, 2, 1, 5, 6, 3, 4, 1, 5. then the experimental probability of getting a 1 is.

The outcome of 120 throws of a die is as shown below

$\begin{matrix} O u t c o m e & 1 & 2 & 3 & 4 & 5 & 6 F r e q u e n c y & 15 & 20 & 22 & 18 & 24 & 21 \end{matrix}$

(i) What is the probability of getting a multiple of 2?
(ii) What is the probability of not getting a 1 or a 6?
(iii) What is the probability of getting a prime?

Q. A number is chosen from

1

50

, what is the probability of getting a prime number ?

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What is the probability of getting a prime number when a die is rolled?

The correct option is B 1/2 Number of prime outcomes when a die is rolled is 3 as 2, 3, 5 are the prime outcomes. Total outcomes = 6. So total probability is 36 = 12

The correct option is B
1/2

Number of prime outcomes when a die is rolled is 3 as 2, 3, 5 are the prime outcomes. Total outcomes = 6. So total probability is $\frac{3}{6}$ = $\frac{1}{2}$