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Question

# What is the probability of obtaining pure homozygous individuals, if a cross is made between AaBbCcDd X aaBBCCdd individuals?

A
116
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B
216
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C
16248
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D
164
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Solution

## The correct option is A 116Number of gametes produced = 2^n, where n is numbers of Heterozygous Gene pairsGenotype AaBbCcDd: Has 4 numbers of Heterozygous Gene pairsSo the number of gametes are 4^4=16The Genotype aaBBCCdd: Homozygous for all the Gene pairs So the gamete produced will be only 1 aBCdTotal 16 male gametes and 1 female gamete produced will result in 16 offsprings.Out of 16, there will be only one genotype aaBBCCdd Homozygous for all genes So the offsprings Homozygous for all gene pairs= 1/16

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