Question

What is the probability that a haemophilic man $\left(X^{h}Y\right)$ and a normal homozygous woman $\left(XX\right)$ produce a haemophilic daughter?

• A. $100\%$
• B. $75\%$
• C. $50\%$
• D. $0\%$

Answer 1

The correct option is C $50\%$

If a man has hemophilic (XhY) and a normal homozygous woman (XX) produce a hemophilic daughter is 50% chances are there.

So, the correct option is '50%'.