The correct option is C 14
Let P(H) be the probability of obtaining head when a coin is flipped.
Total possible outcomes ={H,T}
Favorable outcome ={H}
Number of favorable outcome =1
Total number of outcomes =2
P(H)=Number of favorable outcomeTotal number of outcomes
P(H)=12
Let P(T) be the probability of obtaining tail when a coin is flipped.
Total possible outcomes ={H,T}
Favorable outcome ={T}
Number of favorable outcome =1
Total number of outcomes =2
P(T)=Number of favorable outcomeTotal number of outcomes
P(T)=12
Let P(H and T) denotes the probability of obtaining head followed by a tail. This probability would be obtained by multiplying P(H) and P(T) as both these events are Independent events.
P(H and T)=P(H)×P(T)
P(H and T)=12×12
P(H and T)=14
The probabilty P(H and T) of obtaining a head followed by a tail is 14.
Alternate Solution:–––––––––––––––––––––––
The sample space S obtained when a coin is flipped twice is:
S={HH,HT,TH,TT}
We need to find the probabilty P(H and T) of obtaining a head followed by a tail.
Favorable outcome ={HT}
Number of favorable outcome =1
Total number of possible outcomes =4
P(H and T)=14
The probabilty P(H and T) of obtaining a head followed by a tail is 14.
Therefore, option (c.) is the correct answer.