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Question

What is the probability that a leap year, selected at random will contain
(i) 53 Fridays (ii)53 Mondays and 53 Tuesdays (iii) 53 Sundays and 53 Thursdays.

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Solution

Leap year = 366
52 weeks + 2 days
(i) 53 fridays
probability cases = Thursday, friday or friday, saturday
Total cases = Mon - Tues
Tues - Wed
Wed-Thrusday
Thurs - Friday
Friday - Sat
Sat - Sunday
Sun - mon
probability = 27
(ii) 53 Mondays and 53 Tuesdays
Probability = 17
(iii) 53 Wednesday and 53 Thursdays
No case
Probability = 0

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