Question

What is the probability that a leap year, selected at random will contain
(i) 53 Fridays (ii)53 Mondays and 53 Tuesdays (iii) 53 Sundays and 53 Thursdays.

Answer 1

Leap year = 366
52 weeks + 2 days
(i) 53 fridays
probability cases = Thursday, friday or friday, saturday
Total cases = Mon - Tues
Tues - Wed
Wed-Thrusday
Thurs - Friday
Friday - Sat
Sat - Sunday
Sun - mon
probability = $\frac{2}{7}$
(ii) 53 Mondays and 53 Tuesdays
Probability = $\frac{1}{7}$
(iii) 53 Wednesday and 53 Thursdays
No case
Probability = 0