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Byju's Answer

Standard XII

Chemistry

Addition Reactions

What is the p...

Question

What is the product formed in the given reaction?

2 methyl-1,3 butadiene

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3-methylbut-3-en-1-ol

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3-methylbut-2-en-ol

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None of these

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Solution

The correct option is B 3-methylbut-3-en-1-ol
The given compound on protonation forms a tertiary carbocation which undergoes rearrangement which on further reaction forms allylic alcohol.

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Similar questions

Q. The best method to prepare 3-methylbutan-2-ol from 3-methylbut-1-ene is:

Write structures of the compounds whose IUPAC names are as follows.
(a). 2-methylbutan-2-ol

(b). 1-phenylpropan-2-ol

(c). 3,5-dimethylhexane-1,3,5-triol

(d). 2,3-diethylphenol

(e). 1-ethoxypropane

(f). 2-ethoxy-3-methylpentane

(g). Cyclohexylmethanol

(h). 3-cyclohexylpentan-3-ol

(i). Cyclopent-3-en-1-ol

(j). 3-chloromethylpentan-1-ol

Q. Arrange the following compounds in the decreasing order of their boiling points
(i) Pentan -1- ol (ii) 2-methylbutan -2- ol (iii) 3- Methylbutan–2- ol.

Write structures of the compounds whose IUPAC names are as follows:

(i) 2-Methylbutan-2-ol

(ii) 1-Phenylpropan-2-ol

(iii) 3,5-Dimethylhexane −1, 3, 5-triol

(iv) 2,3 − Diethylphenol

(v) 1 − Ethoxypropane

(vi) 2-Ethoxy-3-methylpentane

(vii) Cyclohexylmethanol

(viii) 3-Cyclohexylpentan-3-ol

(ix) Cyclopent-3-en-1-ol

(x) 3-Chloromethylpentan-1-ol.

Q. 3-Methylbutan-2-ol is:

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What is the product formed in the given reaction?

The correct option is B 3-methylbut-3-en-1-ol The given compound on protonation forms a tertiary carbocation which undergoes rearrangement which on further reaction forms allylic alcohol.

The correct option is B 3-methylbut-3-en-1-ol
The given compound on protonation forms a tertiary carbocation which undergoes rearrangement which on further reaction forms allylic alcohol.