What is the product formed when $C H_{3} C H_{2} C H_{2} C H_{2} - O H$ is reacted with $P C l_{3}$ in presence of trimethyl amine?

C H_{3} C H_{2} C H_{2} C H_{2} - C l

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C H_{3} C H (C H_{3}) C H_{2} C H_{2} - C l

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C H_{3} C H_{2} C (C H_{3})_{2} C H_{2} - C l

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C H_{3} C H_{2} C H_{2} C H_{2} C H_{2} C H_{2} - C l

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Solution

The correct option is A $C H_{3} C H_{2} C H_{2} C H_{2} - C l$
When Alcohol reacts with $P C l_{3}$ in presence of Trimethyl Amine. It is a nucleophile substitution halogenation reaction replaces $O H^{-}$ with $C l^{-}$
$C H_{3} C H_{2} C H_{2} C H_{2} - O H P C l_{3} \to C H_{3} C H_{2} C H_{2} C H_{2} - C l$

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