What is the product of roots of the cubic equation $x^{3}$ -9 $x^{2}$ +16x-30=0 __

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Solution

From the concepts of theory of equations, if a, b. c are roots of given equation,

∑a = a + b + c = - $\frac{(- 9)}{1}$ = 9

∑ab = ab + bc + ca = $\frac{16}{1}$ = 16

∑abc = abc = - $\frac{(- 30)}{1}$ = 30

So, the product of roots = 30

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What is the product of roots of the cubic equation x3-9 x2+16x-30=0 __

From the concepts of theory of equations, if a, b. c are roots of given equation, ∑a = a + b + c = - (−9)1 = 9 ∑ab = ab + bc + ca = 161 = 16 ∑abc = abc = - (−30)1 = 30 So, the product of roots = 30

What is the product of roots of the cubic equation $x^{3}$ -9 $x^{2}$ +16x-30=0 __

From the concepts of theory of equations, if a, b. c are roots of given equation,

∑a = a + b + c = - $\frac{(- 9)}{1}$ = 9

∑ab = ab + bc + ca = $\frac{16}{1}$ = 16

∑abc = abc = - $\frac{(- 30)}{1}$ = 30

So, the product of roots = 30