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Strength of Materials

Mohr's Circle for Stress

What is the r...

Question

What is the radius of Mohr's circle in case of bi-axial state of stress?

A

Half the sum of the two principal stresses

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B

Half the difference of the two principal stresses

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C

Difference of the two principal stresses

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D

Sum of the two principal stresses.

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Solution

The correct option is B Half the difference of the two principal stresses
If $σ_{x} a n d σ_{y}$ are two principal stresses. In biaxial state of stress radius of Mohr's circle
$= \frac{σ_{x} - σ_{y}}{2}$

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