What is the radius of the circle given by the equation ${(x - 3)}^{2} + {(y + 7)}^{2} = 81$

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Solution

The correct option is C 9
Given equation of circle is $(x - 3)^{2} + (y + 7)^{2} = 81$
The center of circle will be $x - 3 = 0$ and $y + 7 = 0$
We get $x = 3$ and $y = - 7$ , therefore the center of circle is $(3, - 7)$
The radius of circle is $\sqrt{81} = 9$ .

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