What is the ratio between AE and AF if EF = 1m ?
2 : √5
We have AB = BC = CD = DE = EF = 1 m
To find AE , we need to find AC, and then AD using Pythagoras theorem.
AC = √12+12 = √2 m
AD = √12+(√2)2 = √1+2 = √3 m
∴ AE = √12+(√3)2 = √1+3 = 2 m
∴ AF = √12+22 = √5 m
Ratio between AE and AF = 2 : √5