Question

What is the ratio for sine of theta?

Answer 1

The ratio of the sine of theta

In a right-angled triangle, theta$\left(\mathrm{\theta }\right)$ is an acute angle, which means it is less than ${90}^{°}$.

The sine is given as the ratio between the opposite side and the hypotenuse of the triangle.

$\sin \left(\mathrm{\theta }\right)=\frac{\mathrm{opposite}\mathrm{side}}{\mathrm{hypotenuse}}$

For example:

If the hypotenuse and the opposite side of a right angles triangle are $5$ units and $3$ units respectively.

Then the ratio sine theta is $=\frac{3}{5}$.