Question

What is the ratio of de Brogile wavelength of deuteron moving with a velocity 2 v and $\alpha$ -particle moving with velocity v ?

• A. 1:1
• B. 1:2
• C. 1:4
• D. 4:1

Answer 1

The correct option is A 1:1

$\lambda =\frac{h}{mv}{\lambda }_d=\frac{h}{2m_p\times 2v}=\frac{h}{4\times m_{p}v}...\left(1\right){\lambda }_{\alpha }=\frac{h}{4m_p\times v}=\frac{h}{4\times m_{p}v}...\left(2\right)$
From (1) and (2)
${\lambda }_d:{\lambda }_{\alpha }=1:1$