Question

What is the ratio of hydrogen and oxygen, liberated by weight, in the electrolysis of water?

• A. $1:16$
• B. $2:8$
• C. $1:8$
• D. $8:1$

Answer 1

The correct option is C $1:8$

$2H_{2}O\to 2H_2+O_2$

The mole ratio of $H_2:O_2=2:1$

$\therefore \frac{\text{Mass}{H}_2}{\text{Mass}{O}_2}=\frac{2\times 2}{1\times 32}=\frac{1}{8}$.

Hence, option C is correct.