Question

What is the ratio of maximum shear stress to average shear stress for a circular section?

• A. 2
• B. 2/3
• C. 4/3
• D. 3/4

Answer 1

The correct option is C 4/3

$Shearstressincircularsection=\frac{4V}{3A}(1-\frac{y^2}{R^2})$

${\tau }_{avg}=\frac{V}{A}$

Maximum shear stress will be at y = 0

${\tau }_{max}=\frac{4}{3}{\tau }_{avg}$