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Chlorination

What is the r...

Question

What is the ratio of monochlorinated product(s) formed from the above reaction, if all the hydrogens were abstracted at equal rates?

A

1 : 1

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B

1 : 3

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C

3 : 1

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D

1 : 9

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Solution

The correct option is D $1 : 9$

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What is the ratio of monochlorinated product(s) formed from the above reaction, if all the hydrogens were abstracted at equal rates?

C H_{3} C H_{2} C H_{2} C H_{3} C l_{2} - - \to h v A + B

(monochlorination products) The approximate ratio of percentage yields of A and B formed in the above reaction is ?

Q. Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon.
Chlorine free radical make

1^{\circ}, 2^{\circ}, 3^{\circ}

radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So , bromine is less reactive, and more selective whereas chlorine is less selective and more effective.
The relative rate of abstraction of hydrogen by Br is

3^{\circ} (1600) > 2^{\circ} (82) > 1^{\circ} (1)

The relative rate of abstraction of hydrogen by Cl is

3^{\circ} (5) > 2^{\circ} (3.8) > 1^{\circ} (1)

F. What would be the product ratio x/y in the chlorination of propane if all the hydrogen were abstracted at equal rate ?

C H_{3} - C H_{2} - C H_{3} C l_{2} - - \to h v C H_{3} - C H_{2} - C (x) H_{2} - C l + C H_{3} - C | C l (y) H - C H_{3}

For the above reaction, given that

X

is a monochlorinated product. The major product

Z

The number of enantiomeric pairs that can be grouped from the products formed by the monochlorination of the compound given above is .

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