Question

What is the ratio of the SI to the CGS units of momentum?

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{The}\mathrm{ratio}\mathrm{of}\mathrm{SI}\mathrm{units}\mathrm{to}\mathrm{CGS}\mathrm{units}\mathrm{of}\mathrm{momentum}\mathrm{is},\mathrm{P}\text{'}=\left(\frac{\mathrm{kg}\mathrm{m}/\mathrm{s}}{\mathrm{g}\mathrm{cm}/\mathrm{s}}\right) \\ 1\mathrm{kg}=1000\mathrm{g} \\ 1\mathrm{m}=100\mathrm{cm} \\ \mathrm{P}\text{'}=\frac{\left(1000\mathrm{g}\times 100\mathrm{cm}\right)/1\mathrm{s}}{\left(1\mathrm{g}\times 1\mathrm{cm}\right)/1\mathrm{s}} \\ \mathrm{P}\text{'}={10}^5 \end{gathered}$$