Question

What is the ratio of time periods $\left(\frac{T_1}{T_2}\right)$ in $2^{nd}$ orbit of hydrogen atom to third orbit of $H{e}^{+}$ ion?

• A. $\frac{8}{27}$
• B. $\frac{32}{27}$
• C. $\frac{27}{32}$
• D. $\frac{27}{8}$

Answer 1

Answer: (B)

$\frac{32}{27}$

$\frac{T_H}{T_{He}}=\frac{n_1^3{t}_2^2}{n_2^3{t}_1^2}$

$=\frac{8\times 4}{3^3}=\frac{32}{27}$

The ratio is $32:27$.