What is the reciprocal of $(- 7)^{4}$ ?

7^{- 4}

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- \frac{1}{(7)^{- 4}}

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\frac{1}{(- 7)^{- 4}}

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\frac{1}{(- 7)^{4}}

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Solution

The correct option is D $\frac{1}{(- 7)^{4}}$
The definition says to take the reciprocal of the base number, and raise it to the corresponding positive power.
so $(- 7)^{4}$ = $\frac{1}{(- 7)^{4}}$

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7^{74} - 4^{74}

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1 + \frac{4}{7} + \frac{9}{7^{2}} + \frac{16}{7^{3}} + \frac{25}{7^{4}} + \dots upto \infty

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Multiplicative inverse of

1) -7/9

2) 13/15

3) 1/3×4/7

4) -13/11×1/5

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