What is the reciprocal product of the roots for the equation $2 x^{2} + 4 x = 0$ ?

one

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Infinity

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zero

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two

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Solution

The correct option is B Infinity
$2 x^{2} + 4 x = 0$
Take $2 x$ common, we get
$2 x (x + 2) = 0$
$2 x = 0, x + 2 = 0$
$x = 0, x = - 2$ are the roots of the equation.
Reciprocal product of the roots $=$ $\frac{1}{0 \times - 2}$ = $\frac{1}{0}$ $=$ infinity

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