What is the reciprocal product of the roots for the equation $48 x^{2} - 6 x + 36$ ?

\frac{4}{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{3}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4}{- 3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{4}{3}$
The general form of complete quadratic equation is $a x^{2} + b x + c = 0$
Where, product of the roots $=$ $\frac{c}{a}$
Here, the given equation is $48 x^{2} - 6 x + 36$
So, the value of $c = 36, a = 48$
Product of the roots $=$ $\frac{36}{48}$ $=$ $\frac{3}{4}$
Reciprocal of the product $=$ $\frac{4}{3}$

Suggest Corrections

Similar questions

\frac{2}{3} x^{2} - \frac{1}{3} x = 0

6 x^{4} - 13 x^{3} - 35 x^{2} - x + 3 = 0, 2 + \sqrt{3}

x^{4} + 2 x^{3} - 8 x^{2} - 6 x + 15 = 0

x^{3} + 4 x^{2} - x - 10 = 0

3 x^{4} + 25 x^{3} + 6 x^{2} + 25 x + 3 = 0

6 x^{4} - 13 x^{3} - 35 x^{2} - x + 3 = 0

2 - \sqrt{3}

Join BYJU'S Learning Program