What is the relation between AM and MB in the given figure?
1:1
In the given figure, consider ΔOAM and ΔOBM.
OA = OB [Radii of the same circle]
OM = OM [Common Side]
OMA = OMB = 90∘ [OM⊥AB]
⇒ ΔOAM ≅ ΔOBM by RHS similarity criterion.
∴ AM = MB (By C.P.C.T)