Question

What is the relation between solubility product and pH?

Answer 1

Dear Student
We know solubility product
Ksp = [A]^a[B]^b
Where A and B are the concentration and a and b are the coefficients.
Now among A and B if any one is H+ or OH- then we can find out pH of the solution.
e.g.
Mg(OH)2 ⇌ Mg2+ + 2OH¯
​Its solubility product
Ksp = [Mg^2+] [OH¯]²
If Ksp is given then we can find out [OH¯]
When the [Mg^2+] = [OH¯]/2
From that we can find out pOH= - log[OH^-]
And at last pH = 14 - pOH
​So in this way we can find out pH when solubility product of the solution is known.


Regards