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Binary Fission

What is the r...

Question

What is the relationship between E_m and E_o

A

E_m=-0.637 E_o

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B

E_m=-0.707 E_o

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C

E_m=-0.737 E_o

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D

E_m=-0.537 E_o

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Solution

The correct option is A
E_m=-0.637 E_o

_{Em=-0.637 Eo}

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Similar questions

Q. Pairs of electrodes and their corresponding standard electrode potentials are given. Arrange the cells constructed by these electrodes in increasing order of emf values.

(a) E l e c t r o d e \to A, E^{o} = - 2.92 V

E l e c t r o d e \to B, E^{o} = - 2.71 V

(b) E l e c t r o d e \to C, E^{o} = - 0.760 V

E l e c t r o d e \to D, E^{o} = - 0.44 V

(c) E l e c t r o d e \to B, E^{o} = - 2.71 V

E l e c t r o d e \to D, E^{o} = - 0.44 V

(d) E l e c t r o d e \to A, E^{o} = - 2.92 V

E l e c t r o d e \to C, E^{o} = - 0.76 V

Q. The standard electrode potentials of the electrodes are given below. Arrange them in decreasing order of ease of oxidation:

(a) E l e c t r o d e - I, E^{o} = - 2.89 V

(b) E l e c t r o d e - I I, E^{o} = - 0.16 V

(c) E l e c t r o d e - I I I, E^{o} = 0.77 V

(d) E l e c t r o d e - I V, E^{o} = - 2.93 V

(e) E l e c t r o d e - V, E^{o} = - 1.67 V

E^{o}

values given, state which statements are correct?

\frac{1}{2} F_{2} + e^{-} ⟶ F^{-}

E^{o}

\frac{1}{2} C l_{2} + e^{-} ⟶ C l^{-}

E^{o}

\frac{1}{2} B r_{2} + e^{-} ⟶ B r^{-}

E^{o}

\frac{1}{2} I_{2} + e^{-} ⟶ I^{-}

E^{o}

Q. From the standard electrode potential values of the electrodes given select an option representing their decreasing order discharge potential:

(a) A, E^{o} = 2.32 V

(b) B, E^{o} = 1.36 V

(c) C, E^{o} = 1.07 V

(c) D, E^{o} = 0.43 V

C o^{3 +} + e^{-} \to C o^{2 +}; E^{o} = + 1.81 V

P b^{4 +} + 2 e^{-} \to P b^{2 +}; E^{o} = + 1.67 V

C e^{4 +} + e^{-} \to C e^{3 +}; E^{o} = + 1.61 V

B i^{3 +} + 3 e^{-} \to B i; E^{o} = + 0.20 V

Oxidizing power of the species will increase in the order :

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