What is the relative molecular mass of CuSO4.5H2O? Given the mass of Cu=63.5 amu
177.5 amu
249.5 amu
877.5 amu
342.0 amu
Cu = 63.5 S = 32 O = 16 H = 2
The relative molecular mass of
CuSO4=63.5+32+(16×4)+5×(2+16)=249.5amu
5.0 g of a certain element X forms 10.0g of its oxide having the formula X4O6. The atomic mass of X is ?
The formula mass of the complex CuSO4.5H2O in grams is y×10−22. Value of y is . (given average atomic mass of Cu = 63.5 u)