Question

What is the remainder? $\frac{(81\times {64}^{25})}{9^4}$

• A. $71$
• B. $10$
• C. $9$
• D. $1$

Answer 1

The correct option is A $71$

$\frac{(81\times {64}^{25})}{9^4}$

$=\frac{3^4{64}^{25}}{3^8}$

$=\frac{{64}^{25}}{3^4}$

Hence, the answer is $71.$