What is the remainder obtained when 96! + 97! Is divided by 9506 is

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Solution

The correct option is C
96

$96! + 97! = 96! \times 98 9506 = 97 \times 98 \frac{(96! + 97!)}{(97 \times 98)} = \frac{96!}{97}$
According to Wilsons theorem the remainder will be 96.

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