What is the remainder obtained when the polynomial $P (x)$ = $x^{7} + 9 x^{5} + 5 x^{3} + x - 1$ is divided by $x - 1$ ?

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Solution

The correct option is A 15
As per remainder theorem, the remainder obtained when the polynomial is divided by $x - 1$ will be same as the value of the polynomial at $x = 1$ .
$P (1) = 1^{7} + 9 \times {(1)}^{5} + 5 \times {(1)}^{3} + 1 - 1 = 15$ .
Thus remainder when $x^{7} + 9 x^{5} + 5 x^{3} + x - 1$ is divided by $x - 1$ is 15.

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What is the remainder obtained when the polynomial P(x) = x7+9x5+5x3+x−1 is divided by x–1?

The correct option is A 15As per remainder theorem, the remainder obtained when the polynomial is divided by x−1 will be same as the value of the polynomial at x=1. P(1)=17+9×(1)5+5×(1)3+1−1=15. Thus remainder when x7+9x5+5x3+x−1 is divided by x–1 is 15.

What is the remainder obtained when the polynomial $P (x)$ = $x^{7} + 9 x^{5} + 5 x^{3} + x - 1$ is divided by $x - 1$ ?