The correct option is C 3
We know that 5! or greater than 5! will be divisible by 5, Therefore, when (1! + 2! + 3!...1000!) is divisible by 5 equals to when (1! + 2! + 3! + 4!) is divided by 5. we get the remainder as
1!+2!+3!+4!5=335=35
Hence, remainder obtained = 3