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Question

What is the remainder when 102×205 is divided by 3?

A
0
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B
1
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C
2
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D
3
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Solution

The correct option is A 0
102×205=20,910
20,910÷3=6970
Since the sum of the divisor digits =2+0+9+1+0=12 is divisible by 3.
So, the remainder is 0.

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